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What is the output of the following code?
#include <iostream>
using namespace std;
struct Node {
    int data;
    Node* next;
};
void insertAtEnd(Node** head, int value) {
    Node* newNode = new Node();
    newNode->data = value;
    newNode->next = NULL;
    if (*head == NULL) {
        *head = newNode;
    } else {
        Node* current = *head;
        while (current->next != NULL) {
            current = current->next;
        }
        current->next = newNode;
    }
}
void printList(Node* head) {
    Node* current = head;
    while (current != NULL) {
        cout << current->data << " ";
        current = current->next;
    }
}
int main() {
    Node* head = NULL;
    insertAtEnd(&head, 1);
    insertAtEnd(&head, 2);
    insertAtEnd(&head, 3);
    printList(head);
    return 0;
}
  • a)
    1 2 3
  • b)
    3 2 1
  • c)
    3
  • d)
    1
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
What is the output of the following code?#include <iostream>usin...
The code creates a linked list and inserts three elements at the end using the insertAtEnd function. The printList function outputs the elements of the linked list.
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What is the output of the following code?#include <iostream>usin...


Explanation:

insertAtEnd Function:
- This function inserts a new node at the end of the linked list.
- It creates a new node with the given value and sets its next pointer to NULL.
- If the head of the linked list is NULL, it assigns the new node as the head.
- Otherwise, it traverses the linked list to find the last node and appends the new node to it.

printList Function:
- This function prints the data of each node in the linked list.
- It starts from the head of the linked list and prints the data of each node until it reaches the end (NULL).

Main Function:
- Initializes the head of the linked list as NULL.
- Calls insertAtEnd function three times to insert nodes with values 1, 2, and 3.
- Finally, calls printList function to print the data of all nodes in the linked list.

Output:
- The output of the code will be "1 2 3" because the nodes are inserted at the end of the linked list in the order 1, 2, 3.
- When the printList function is called, it traverses the linked list starting from the head and prints the data of each node, resulting in "1 2 3" being displayed on the console.
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What is the output of the following code?#include <iostream>using namespace std;struct Node { int data; Node* next;};void insertAtEnd(Node** head, int value) { Node* newNode = new Node(); newNode->data = value; newNode->next = NULL; if (*head == NULL) { *head = newNode; } else { Node* current = *head; while (current->next != NULL) { current = current->next; } current->next = newNode; }}void printList(Node* head) { Node* current = head; while (current != NULL) { cout << current->data << " "; current = current->next; }}int main() { Node* head = NULL; insertAtEnd(&head, 1); insertAtEnd(&head, 2); insertAtEnd(&head, 3); printList(head); return 0;}a)1 2 3b)3 2 1c)3d)1Correct answer is option 'A'. Can you explain this answer?
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What is the output of the following code?#include <iostream>using namespace std;struct Node { int data; Node* next;};void insertAtEnd(Node** head, int value) { Node* newNode = new Node(); newNode->data = value; newNode->next = NULL; if (*head == NULL) { *head = newNode; } else { Node* current = *head; while (current->next != NULL) { current = current->next; } current->next = newNode; }}void printList(Node* head) { Node* current = head; while (current != NULL) { cout << current->data << " "; current = current->next; }}int main() { Node* head = NULL; insertAtEnd(&head, 1); insertAtEnd(&head, 2); insertAtEnd(&head, 3); printList(head); return 0;}a)1 2 3b)3 2 1c)3d)1Correct answer is option 'A'. Can you explain this answer? for Software Development 2024 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about What is the output of the following code?#include <iostream>using namespace std;struct Node { int data; Node* next;};void insertAtEnd(Node** head, int value) { Node* newNode = new Node(); newNode->data = value; newNode->next = NULL; if (*head == NULL) { *head = newNode; } else { Node* current = *head; while (current->next != NULL) { current = current->next; } current->next = newNode; }}void printList(Node* head) { Node* current = head; while (current != NULL) { cout << current->data << " "; current = current->next; }}int main() { Node* head = NULL; insertAtEnd(&head, 1); insertAtEnd(&head, 2); insertAtEnd(&head, 3); printList(head); return 0;}a)1 2 3b)3 2 1c)3d)1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Software Development 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the output of the following code?#include <iostream>using namespace std;struct Node { int data; Node* next;};void insertAtEnd(Node** head, int value) { Node* newNode = new Node(); newNode->data = value; newNode->next = NULL; if (*head == NULL) { *head = newNode; } else { Node* current = *head; while (current->next != NULL) { current = current->next; } current->next = newNode; }}void printList(Node* head) { Node* current = head; while (current != NULL) { cout << current->data << " "; current = current->next; }}int main() { Node* head = NULL; insertAtEnd(&head, 1); insertAtEnd(&head, 2); insertAtEnd(&head, 3); printList(head); return 0;}a)1 2 3b)3 2 1c)3d)1Correct answer is option 'A'. Can you explain this answer?.
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